In Scala, you can get the path of the sibling directory (sister directory) by using the java.io.File class and its getParent() method.
Here's an example:
import java.io.File
// create a file object that represents a file in the sibling directory
val file = new File("../sibling_dir/example.txt")
// get the path of the parent directory
val parent = file.getParent()
// get the path of the sibling directory by joining the parent path with the sibling directory name
val sibling = new File(parent, "sibling_dir")
// display the path of the sibling directory
println(sibling.getPath())
In this example, we first create a File object that represents a file in the sibling directory using a relative path (../sibling_dir/example.txt). Then we get the path of the parent directory by calling the getParent() method on the file object. Next, we create a new File object for the sibling directory by joining the parent path with the sibling directory name (sibling_dir). Finally, we display the path of the sibling directory using the getPath() method.
Note that the relative path (../sibling_dir/example.txt) assumes that the current working directory is a directory that contains both the current directory and the sibling directory. If the current working directory is different, you may need to adjust the relative path accordingly.