Select find all in Java 20

To find all the elements of an array satisfying a condition in Java 20, you can use the Java Streams API.

Here's an example code snippet to demonstrate this:

import java.util.Arrays;
import java.util.stream.Collectors;
public class Main {

    public static void main(String[] args) {

        // Create an array of integers

        int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
// Find all elements of the array which are greater than 5

        int[] filteredNumbers = Arrays.stream(numbers)

                .filter(n -> n > 5)

                .toArray();
// Print the filtered array

        System.out.println(Arrays.toString(filteredNumbers));
// Find all elements of the array which are even

        int[] evenNumbers = Arrays.stream(numbers)

                .filter(n -> n % 2 == 0)

                .toArray();
// Print the array with even numbers

        System.out.println(Arrays.toString(evenNumbers));

        

        // Find all elements of the array which are less than 5 and greater than 2

        int[] betweenTwoAndFive = Arrays.stream(numbers)

                .filter(n -> n > 2 && n < 5)

                .toArray();
// Print the array with numbers between 2 and 5

        System.out.println(Arrays.toString(betweenTwoAndFive));

    }

}

Output:

[6, 7, 8, 9, 10] // Filtered array with numbers greater than 5
[2, 4, 6, 8, 10] // Filtered array with even numbers
[3, 4] // Filtered array with numbers between 2 and 5

In the code above, we use the Arrays.stream() method to create a stream of elements from the array, and then we use the filter() method to apply the condition to each element in the stream. Finally, we use the toArray() method to convert the filtered stream back into an array.