In Go, you can convert a string to an integer using the strconv package. Here's an example:
package main
import (
"fmt"
"strconv"
)
func main() {
str := "123"
num, err := strconv.Atoi(str)
if err != nil {
fmt.Println("Error:", err)
} else {
fmt.Println("String:", str)
fmt.Println("Integer:", num)
}
}
In this example, we first declare a string variable str that contains the value "123". Then we use the strconv.Atoi() function to convert str to an integer variable called num. The Atoi() function returns two values: the converted integer and an error. We use a conditional statement to handle the case where an error occurs during the conversion process. If there are no errors, we print the original string and the converted integer using fmt.Println().
Output:
String: 123
Integer: 123
You can also use strconv.ParseInt() function to convert a string to integer, which is more flexible as it allows you to specify the number base (e.g. binary, decimal, hexadecimal). Here's an example:
package main
import (
"fmt"
"strconv"
)
func main() {
str := "1010"
num, err := strconv.ParseInt(str, 2, 64)
if err != nil {
fmt.Println("Error:", err)
} else {
fmt.Println("String:", str)
fmt.Println("Integer:", num)
}
}
In this example, we convert the string "1010" to an integer using strconv.ParseInt(), specifying that the number is in binary format (base 2) and that the result should be of type int64. The resulting integer variable num will contain the value 10 in decimal format.
Output:
String: 1010
Integer: 10